Imagine you have a special keyboard with the following keys:
Key 1: Prints 'A' on screen
Key 2: (Ctrl-A): Select screen
Key 3: (Ctrl-C): Copy selection to buffer
Key 4: (Ctrl-V): Print buffer on screen appending it after what has already been printed.
If you can only press the keyboard for N times (with the above four keys), write a program to produce the maximum number of A's. The input is the number of times you can press the keyboard and the output is the maximum number of A’s that you can produce.
Input: int press = 11; Output: 27 Explanation: By pressing 11 times on the keyboard you get the maximum of 27 A’s on the screen with the following keyboard combinations: A, A, A, Ctrl A, Ctrl C, Ctrl V, Ctrl V, Ctrl A, Ctrl C, Ctrl V, Ctrl V |
Solution:
1. static int getMaxLetters(int press) { 2. if (press <= 6) { 3. return press; 4. } 5. 6. int[] maxLetters = new int[press]; 7. 8. for (int i = 1; i <= 6; i++) { 9. maxLetters[i - 1] = i; 10. } 11. 12. for (int i = 7; i <= press; i++) { 13. maxLetters[i - 1] = Math.max(2 * maxLetters[i - 4], Math.max(3 * maxLetters[i - 5], 4 * maxLetters[i - 6])); 14. } 15. return maxLetters[press - 1]; 16. } 17.