top of page
Caută
Poza scriitoruluioanaunciuleanu

Interpolation Search in C++


Interpolation Search algorithm is used to search for a value in an ordered, uniformly distributed array of elements. Interpolation Search will go to different locations to start with, depending if the searched value is closer to the end or the start of the array, unlike Binary Search that is always looking for the middle. So, this technique is trying to find the exact location of the value, not the middle, using the interpolation formula. The search time is reduced, since it tries to find the best approximation of the position every time.



// Interpolation Search
#include <iostream>

int InterpolationSearch(int arrayOfNumbers[], int numberOfElements, int searchForNumber)
{
	// We are searching for values between indexes left and right
	int left = 0;
    int right = numberOfElements - 1;
    int estimatedMiddle = 0;

	while (arrayOfNumbers[right] != arrayOfNumbers[left] && searchForNumber >= arrayOfNumbers[left] && searchForNumber <= arrayOfNumbers[right])
	{
		// We estimate the middle index
		estimatedMiddle = left + ((searchForNumber - arrayOfNumbers[left]) * (right - left) / (arrayOfNumbers[right] - arrayOfNumbers[left]));

		if (searchForNumber == arrayOfNumbers[estimatedMiddle])
        {
            printf("The number %d is found at index %d", searchForNumber, estimatedMiddle);
            return estimatedMiddle;
        }


		// If the value is smaller than the one from the middle, we look only at the left part of the array
		else if (searchForNumber < arrayOfNumbers[estimatedMiddle])
        {
            right = estimatedMiddle - 1;
        }

		// If the value is greater than the one from the middle, we look only at the right part of the array
		else
			left = estimatedMiddle + 1;
	}

	if (searchForNumber == arrayOfNumbers[left])
    {
        printf("The number %d is found at index %d", searchForNumber, left);
        return left ;
    }

	else
    {
        printf("The number %d was not found in the array", searchForNumber);
        return -1;
    }
}

int main(void)
{
	int arrayOfNumbers[] = {1, 3, 5, 6, 8, 10, 11, 14};
	int searchForNumber = 11;

	int numberOfElements = sizeof(arrayOfNumbers)/sizeof(arrayOfNumbers[0]);
	int result = InterpolationSearch(arrayOfNumbers, numberOfElements, searchForNumber);
	return 0;
}

218 afișări0 comentarii

Postări recente

Afișează-le pe toate

Weighted Job Scheduling in JAVA

You receive a list of jobs that have three elements: start time, finish time and profit. You have to schedule the jobs with no...

Tiling Problem in JAVA

You can use a board that is 2 x n size. The tiles are of size 2 x 1. Count the number of ways to tile the board. Tiles can be placed...

Comments


bottom of page